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Solutions - Assignment 6 New
Solutions | Approved: 7 years ago | 413.24 kB | Comments: 0
Category: Calculus | Downloaded: 0
...evalf(f(1));0.5235987758 � evalf(f(sqrt(2)-1));0.7931048180 Absolute min of ~0.53...
...x = 1 and absolute max of...
...= 1 and absolute max of ~0.79...
...evalf(f(0));0.3400873809 � evalf(f(1));0.1275327679 Absolute min of ~0.12...
...= 1 2 and absolute max of...
...1 2 and absolute max of ~0.34...
N/A 175 blithering
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